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Can anyone help me to solve this problem , How may signals chlorocyclohexane would produce? Thanks
Can anyone help me to solve this problem , How may signals chlorocyclohexane would produce? Thanks
Can anyone help me to solve this problem , How may signals chlorocyclohexane would produce? Thanks
4 peaks.
1 quartet
3 quintet
Bruin is right. 1 Quartet and 3 quintets.
Simiam, how many types of hydrogens are in this molecule? The answer is 4, and not 6. Remember, you don't count the similar hydrogens again. I guess you are counting the similar type of hydrogens again, and that is why you end up with so many quintets. the Hydrogens at C4 have 4 surrounding hydrogens, but that is not gonna give you a quintet, because the two Hydrogens on the C3 are similar hydrogens to the ones on C5. So you count only two of them [not 4!], and that gives you a triplet. Use the same rule for the rest.
Correct me if I'm wrong and Brian is right...
So, based on what you have said, propane, CH3CH2CH3, must have a quartet and a triplet. An interesting theory...
So, based on what you have said, propane, CH3CH2CH3, must have a quartet and a triplet. An interesting theory...
Bruin, refer to the answer by doc toothache. That is what I'm talking about. I know there is a rule like that. I sent you a message about this. I will get back to you once I review this session.
I think your answer and reasoning are somewhat different from doc toothache's?
So doc toothache, based on what you have said, 2-methyl-butanol, CH3CH2CHCH3CH2OH, should give octet on C3?
This spectrum shows a heptet and a triplet. It is exactly proving my point.
CH3CH2CH (CH3)CH2OH
In 2- methylbutanol, the hydrogen on C2 is expected to be split by the -CH3 hydrogens into a doublet. Since the hydrogens on C1 and C3 are in slightly different environment and are, therefore, non equivalent, further spliting is expected.
http://www.fao.org/ag/agn/jecfa-flav/img/img/1199.gif
(click on the spectrum to see a larger image with the hydrogen assignments)
Theoretically, the C2 hydrogens in propane should be a quartet since the two methyl groups are equivalent. Why in real life this is not so is a question you will have to ask a chem prof. In the meantime, we may be making this more complicated than it needs to be. In real life the NMR spectra may be a little different than predicted for whatever reason. For example, in the case of chlorocyclopropane, the C 1 hydrogen can be in either axial or equatorial position, and depending on the experimental conditions we may or may not have a 50:50 mixture. You can pretty much bet that the DAT material will stick to basics since otherwise it would require some experience in both advanced organic chemistry and NMR spectroscopy.
Very interesting. I will have to read more of O.chem textbook to fully understand your reasoning. Thank you for enlightening me.
This spectrum shows a heptet and a triplet. It is exactly proving my point.
C1 H = triplet (split by the C2 hydrogens)
C2 H2 =sextet (split into triplet by C3 H2 and each triplet is split into a doublet by C1 H)
C3 H2 = triplet (C2 and C4 have equivalent hydrogens) -how are C2 & C4 hydrogens similar? C2 hydrogens are closer to chlorine than C4. I don't understand.
C4 H2 = triplet (C3 and C5 have equivalent hydrogens) - I understand why these are similar
http://www.sigmaaldrich.com/catalog/search/ProductDetail/ALDRICH/C105058
http://www.sigmaaldrich.com/spectra/fnmr/FNMR009613.PDF
I agree with Bruinlove...
C1 - quintet
C2 - quartet
C3 - quintet
C4 - quintet