- Joined
- May 1, 2008
- Messages
- 79
- Reaction score
- 0
Hey guys, I'm working on a lab report and I'm stuck. I have spent over an hour trying to figure this stinker out and still no luck. See if you guys can help out.
Find ∆H for the reaction, HCl(g) + H2O(l) à HNO2(l) + Na2O (s), given:
2 NaCl(s) + H2O(l) à 2 HCl(g) + Na2O(s); ∆H = 507 kJ
NO(g) + NO2(g) + Na2O(s) à 2 NaNO2(s); ∆H = -427 kJ
NO(g) + NO2(g) à N2O(g) + O2(g); ∆H = -43 kJ
2 HNO2(l) à NO2(g) + O2(g) + H2O(l); ∆H = 34 kJ
Thanks in advance!
Find ∆H for the reaction, HCl(g) + H2O(l) à HNO2(l) + Na2O (s), given:
2 NaCl(s) + H2O(l) à 2 HCl(g) + Na2O(s); ∆H = 507 kJ
NO(g) + NO2(g) + Na2O(s) à 2 NaNO2(s); ∆H = -427 kJ
NO(g) + NO2(g) à N2O(g) + O2(g); ∆H = -43 kJ
2 HNO2(l) à NO2(g) + O2(g) + H2O(l); ∆H = 34 kJ
Thanks in advance!