Hofmann elimination

[hasanein4u]

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hey guys,

Just to make sure I got this concept correctly

Hofmann elimination is producing the least substituted alkene in two cases:

elimination reaction by tertiary base (bulky)
or
amine with methyl 1)Methyl Iodide 2)Ag2O/H2O 3)Heat


Am I right?

 

[ReaverOpS]

Yep.

 

[hasanein4u]

Chad says that it has to be tertiary base and tertiary alkyl hadile (BOTH)... if the base is tertiary and the alkyl halide is not then we do not do it at the least substituted carbon.... while other sources says if the base is tertiary that is enough to eliminate from the least substituted carbon even if the alkyl halide is not tertiary

what do you guys think?

 

[ReaverOpS]

It really depends on the specifics of the problem. Both can occur.