LEE ADAMA WILLIAMS
Full Member
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- Sep 29, 2019
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been working on this problem all day and it doesn't make any sense to me
"find the molar solubility of calcium hydroxide in a solution buffered at each of the following pH's"
a. ph=4
b. ph=7
c. ph=9
Here's what I did for the first part
ph=4 , pOH=10
[OH] = 1.0E-10
Ca(OH)2 ---> Ca+2 + 2OH-
I - 1.0E-10M
C +x 1.0E-10M+2x
E x (1.0E-10M + 2x)^2
Ksp = 4.68E-6
I can plug in these values directly and wont get a reasonable answer for x
I have also figured that since the Ksp is orders of magnitude greater than the initial hydroxide concentration we can ignore it and thus assume its just the same as aqueous
the answer should be: 5*10^14M
wasted 5 hours of my life on this... hate myself
"find the molar solubility of calcium hydroxide in a solution buffered at each of the following pH's"
a. ph=4
b. ph=7
c. ph=9
Here's what I did for the first part
ph=4 , pOH=10
[OH] = 1.0E-10
Ca(OH)2 ---> Ca+2 + 2OH-
I - 1.0E-10M
C +x 1.0E-10M+2x
E x (1.0E-10M + 2x)^2
Ksp = 4.68E-6
I can plug in these values directly and wont get a reasonable answer for x
I have also figured that since the Ksp is orders of magnitude greater than the initial hydroxide concentration we can ignore it and thus assume its just the same as aqueous
the answer should be: 5*10^14M
wasted 5 hours of my life on this... hate myself