It's a qvault question: correct answer is to the right. How is this possible? I thought it would go to the left when precipitation forms? What is the reasoning behind this?
How will formation of an insoluble product shift the equilibrium?
- Thread starter rak173
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When looking at chemical equilibrium, we have to use K which is a function of concentration. Formation of a solid essentially takes species out of solution thus lowering its concentration (only aqueous and gases are included) The reaction will correct itself by shifting to restore the balance of concentrations. So if you form a solid product, you lose the concentration of product species and the reaction must shift to the right in order to maintain the Keq value. Loss of Product (solid precipitate leaving aqueous solution)= equilibrium shifts right to balance product
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^^ kimball is spot on. The way Chad explains it is a fun way of thinking about it...
Chad said something about how when an insoluble product forms, it is as if the products turn into frogs and jump out of the solution. The same thing occurs if your product is a base, such as OH-, and you add in an acid. They will react to form water, and it is as if the OH- turned into a frog and left the solution, causing equilibrium to shift right.
Chad said something about how when an insoluble product forms, it is as if the products turn into frogs and jump out of the solution. The same thing occurs if your product is a base, such as OH-, and you add in an acid. They will react to form water, and it is as if the OH- turned into a frog and left the solution, causing equilibrium to shift right.
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well I thought IN THIS CONTEXT its more like when the solid forms, it doesnt contribute to the equilibrium,.. however, the concentration of the reactants decreases... and 1/[reactant] increases... shifting the equilibrium value to the right
idk qvault gives me cancer for some reason
idk qvault gives me cancer for some reason
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well he uses the spell "abracadabra"
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another explanation i got was that formation of insoluble product shifts equilibrium to the right b/c it's samething as taking away reactants while not contributing to the reverse rxn..
hope you destroy the DAT tomorrow!!
