If Keq forward vs. reverse

[SaintJude]

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If the equilibrium constant for a forward formation reaction is 6 x 10^5. What is the equilibrium of the decomposition (the reverse) reaction? 1/(6 x 10^5) ?

 

[milski]

Yes. If Ka=[A][C]../[X][Y][Z].., then the reverse is just [X][Y][Z]../[A][C]... which is 1/Ka

 

[MedPR]

If the equilibrium constant for a forward formation reaction is 6 x 10^5. What is the equilibrium of the decomposition (the reverse) reaction? 1/(6 x 10^5) ?

Yup. Keq = [product]/[reactant] So if 10 = [product]/[reactant] then 0.1 = [reactant]/[product]

 

[SaintJude]

When Milski's is in the forum...you know there's an answer on the way. 🙂 Thank you so much!