If the limit is 50 words, how many more words can you add?

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I was just wondering if it would ok if i have around 70 words for a 50 word limit question.

It is a limit for a reason. If you don't follow it they will think 2 things:

1.) Why is this guy making me read more than everyone else? Well ok, if he wants me to take the extra time to read some extra stuff, it better be damned special OR ELSE...

2.) Wow this guy can't follow a simple instruction.


Penn State gets a hell of alot of apps each year. That's why they are so short, cuz they don't have the time to read 30000 rantings of premeds with issues.
 
agreed. keep it to 50.
 
I was just wondering if it would ok if i have around 70 words for a 50 word limit question.

(As pre-med machine)

Why would you write 70 words? That is 40 percent more words than necessary. That's just bunk! Would you write 1500 words for a 1000 word essay? What if everyone wrote 40 percent more words? Then they would ask for 40 percent more pay and raise the secondary fees by 40 percent. Bunk!

The proper formula for extra essay words is: W(e)= .80P + .10Wp + .20Cp, where P is number of paragraphs used, Wp is the number of required words specified in the prompt, and Cp is level of competitiveness.

If you have not already determined a quantitative formulation for your relative competitiveness, Cp can be substituted by your "NUMBER", as determined by LizzyM, who, I should clarify, is most likely (~1/150 odds) not a member of the Harvard adcomm, but an adcomm member nonetheless. This should give you a result that is accurate to the hundredths of a decimal, which is why, of course, I used 2 significant figures in the formula above.
 
(As pre-med machine)

Why would you write 70 words? That is 40 percent more words than necessary. That's just bunk! Would you write 1500 words for a 1000 word essay? What if everyone wrote 40 percent more words? Then they would ask for 40 percent more pay and raise the secondary fees by 40 percent. Bunk!

The proper formula for extra essay words is: W(e)= .80P + .10Wp + .20Cp, where P is number of paragraphs used, Wp is the number of required words specified in the prompt, and Cp is level of competitiveness.

If you have not already determined a quantitative formulation for your relative competitiveness, Cp can be substituted by your "NUMBER", as determined by LizzyM, who, I should clarify, is most likely (~1/150 odds) not a member of the Harvard adcomm, but an adcomm member nonetheless. This should give you a result that is accurate to the hundredths of a decimal, which is why, of course, I used 2 significant figures in the formula above.


Yeh. What he said.
 
If it's an electronic text box, it may cut you off at 50 (or just stop showing words when you run out of space, giving the impression that you broke off mid-sentence)

One easy way to get rid of extra words: avoid passive-voice constructions (rewrite "I was thinking" as "I thought"). Another: avoid empty phrases, such as "the fact that..."

Make sure you really need every word you use, and that they're good strong ones, and you can say plenty in 50 words.
 
If it's an electronic text box, it may cut you off at 50 (or just stop showing words when you run out of space, giving the impression that you broke off mid-sentence)

One easy way to get rid of extra words: avoid passive-voice constructions (rewrite "I was thinking" as "I thought"). Another: avoid empty phrases, such as "the fact that..."

Make sure you really need every word you use, and that they're good strong ones, and you can say plenty in 50 words.

I'm sorry. The above post has exceeded 50 words and must be deleted. :meanie:
 
there exists a 75 extra word safety net in secondaries.
 
If they said 50, they don't want your 70, 20 extra words is a lot on a 50 word question. So stop boring them to death with your rambling 70 word answer and get to the point. 😀
 
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