P.S. I tried using Change in T = i m k
but i didn't get the answer... :''''(
A 1.50 gram sample of urea is dissolved in 105 grams of water and produces a solution that boils at 100.12 degrees C. From this data, what is the molecular mass of urea?
Given:
MW of Urea: ?
Mass of urea: 1.50 g
dT = 0.12
mass of water: 105g = 0.105 kg
Kb of water ~ 0.5 (should be given..)
i = 1, as urea does not dissociate into ions
Equations:
1) dT = Kb*molality*i
2) molality = moles urea/mass water
3) moles urea = mass urea/MW urea
Combining 2+3, we get:
4)molality = mass urea / (mass water)*(MW urea)
Combining 1+4, we get:
dT = Kb*molality*i
dT = (Kb*massU*i) / (massW*MW)
MW = (Kb*massU*i) / (massW*dT)
MW = (0.5*1.5*1 / (0.105*0.12)
MW = 0.75/ 0.0126
MW ~ 60
Hope you had a calc to help u out with this, if you did it fast (with rounding, you would get something around 75 g/mol, which is pretty close to the actual answer), but I guess it will depend there what are the answer choices.
eg.
MW = (0.5*1.5*1) / (0.1*0.1)
MW = 0.75/0.01
MW = 75
From rounding, we decreased the denominator, so we know the real answer should be less than 75.