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I always thought LDA was bulky base so it would attack the H of the least substituted Carbon, but destroyer shows that C2H5O-+Na does the same (ie: problem 85 & 123 of 2008 version)?
Isnt C2H5O- (aka EtO-) a smaller base so it attacks more substituted carbons😕
Isnt C2H5O- (aka EtO-) a smaller base so it attacks more substituted carbons😕