Isomers

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keliao

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188. how many isomers (constitutional) can be drawn for C4 H10 O ?
ans. B 7
a.6 b. 7 c.5 d. 8 e. 10

seriously.. do i need to draw all of them out???? is there any shortcut?
 
It doesn't take that long. Just start out without branching and then add one at a time.
 
It's also good to know the degree of unsaturation formula:

(2*C + 2 - H)/2 ... in this case (2*4 + 2 - 10) = 0 ... so no double bonds or rings. So the isomers are only saturated alcohols and ethers. After that, just draw it out...
 
I got 7 for my answer. Is that correct??

Keliao said it is 7 isomers. But I am getting 8 isomers.🙁 Can you explain me how did you get it? please. I draw them out then count the possible location of the Hydrogen for the isomers.
 
The isomers are:

n-butanol
2-butanol
isobutanol (2-methylpropanol)
t-butanol (2-methyl-2-propanol)

methyl propyl ether (methoxypropane)
diethyl ether (ethoxyethane)
isopropyl methyl ether (2-methyoxypropane)
 
The isomers are:

n-butanol
2-butanol
isobutanol (2-methylpropanol)
t-butanol (2-methyl-2-propanol)

methyl propyl ether (methoxypropane)
diethyl ether (ethoxyethane)
isopropyl methyl ether (2-methyoxypropane)


Yeeik, I saw what I did.

Code:
 CH3-CH2-CH-CH3
         |    
        OH  

and 
         CH3-CH2-CH-OH
                  |    
                 CH3

Thanks.
 
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