Kaplan Discretes Test 1 (Capacitance)

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Synapsis

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8. A parallel plate capacitor is connected across a constant emf source. If the separation of the plates is decreased, which of the following will increase?

I. Charge on the plates of the capacitor
II. Potential difference between the plates
III. Capacitance

So III is a definite yes by C = keA / D. And if capacitance increases at a constant voltage, that implies Q increases by C = Q / V. But if the potential difference across the plates is given by dPE = (1/2)CV^2, and V is constant while C increases, why doesn't dPE increase?
 
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