azor ahai Full Member 7+ Year Member Joined May 30, 2014 Messages 252 Reaction score 111 Points 4,651 Dec 17, 2014 #1 Members do not see this ad. Why do they count O2?
Cawolf PGY-2 10+ Year Member Joined Feb 27, 2013 Messages 3,469 Reaction score 2,287 Points 5,246 Resident [Any Field] Dec 17, 2014 #2 Because you have to break an O=O bond to form the product. There are O=O bonds in the reactants but not in the products. Last edited: Dec 17, 2014 Upvote 0 Downvote
Because you have to break an O=O bond to form the product. There are O=O bonds in the reactants but not in the products.
azor ahai Full Member 7+ Year Member Joined May 30, 2014 Messages 252 Reaction score 111 Points 4,651 Dec 17, 2014 #3 Cawolf said: Because you have to break an O=O bond to form the product. Click to expand... But isn't O2's enthalpy of formation = 0? Upvote 0 Downvote
Cawolf said: Because you have to break an O=O bond to form the product. Click to expand... But isn't O2's enthalpy of formation = 0?
Cawolf PGY-2 10+ Year Member Joined Feb 27, 2013 Messages 3,469 Reaction score 2,287 Points 5,246 Resident [Any Field] Dec 17, 2014 #4 The passage doesn't provide enthalpies of formation, it provides bond dissociation energies. dH = BDE broken - BDE formed not dH = dHf (products) - dHf (reactants) Upvote 0 Downvote
The passage doesn't provide enthalpies of formation, it provides bond dissociation energies. dH = BDE broken - BDE formed not dH = dHf (products) - dHf (reactants)
azor ahai Full Member 7+ Year Member Joined May 30, 2014 Messages 252 Reaction score 111 Points 4,651 Dec 18, 2014 #5 Cawolf said: The passage doesn't provide enthalpies of formation, it provides bond dissociation energies. dH = BDE broken - BDE formed not dH = dHf (products) - dHf (reactants) Click to expand... Oooooh. Thanks! Upvote 0 Downvote
Cawolf said: The passage doesn't provide enthalpies of formation, it provides bond dissociation energies. dH = BDE broken - BDE formed not dH = dHf (products) - dHf (reactants) Click to expand... Oooooh. Thanks!