kaplan subject tests

[SunnyD0119]

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hey guys i wanted to ask those of you who took the kaplan subject tests (you know when you pay for their course) the chem and bio subject tests are pretty damn hard and i wanted to ask if thats how the real dat is like?
thanks

 

[Zayna06]

hey guys i wanted to ask those of you who took the kaplan subject tests (you know when you pay for their course) the chem and bio subject tests are pretty damn hard and i wanted to ask if thats how the real dat is like?
thanks

The gen chem section on the real DAT is much easier. It has more concept problems than calculation problems on it. The bio depends, since it is a very broad subject, covering lots of material. When I took the DAT, I got lots of very specific questions about animal species that I would never have even thought I would need to study and one of my friends got lots of plant stuff (which I didn't get a single question about on my exam). Hope this helps.

 

[QUDMD]

the chem section on the actual dat was on par (if not slightly easier) than the Kaplans. The bio section is another matter. Straight A's in college in bio, tons of hours studying the bio section in Kaplan, nailing the Bio section on those tests with steady 22-24's, but I received a 19 on the actual. I found the bio questions on the test to be really in-depth. Some of the bio q's however were EXACT copies of some I've seen on Kaplan, which speeded things up. Not to worry, however, I'm not the best standardized test taker. By the way, the o-chem section was a piece of cake. i actually enjoyed it.

 

[katieTX]

the chem section on the actual dat was on par (if not slightly easier) than the Kaplans. The bio section is another matter. Straight A's in college in bio, tons of hours studying the bio section in Kaplan, nailing the Bio section on those tests with steady 22-24's, but I received a 19 on the actual. I found the bio questions on the test to be really in-depth. Some of the bio q's however were EXACT copies of some I've seen on Kaplan, which speeded things up. Not to worry, however, I'm not the best standardized test taker. By the way, the o-chem section was a piece of cake. i actually enjoyed it.

So it means that o-chem subject tests are harder than real DAT also?
I'm worried about my o-chem. Thanks 4 input.

 

[drengineer]

As far as i have heard most sections are harder on Kaplan (except for PAT) than on the real DAT.

 

[dexadental]

I thought the chemistry from Kaplan is pretty easy, just learn the material and the problems are a cinch. The bio is where my trouble is...Also, the organic is really easy!

 

[SunnyD0119]

I thought the chemistry from Kaplan is pretty easy, just learn the material and the problems are a cinch. The bio is where my trouble is...Also, the organic is really easy!

See on kaplan subject tests they want you to solve for x using like 3rd root 4.5 x10^-8 all over 4 i dont know how to do that crap in my head?
are there calcs like this on the real deal?

 

[drengineer]

See on kaplan subject tests they want you to solve for x using like 3rd root 4.5 x10^-8 all over 4 i dont know how to do that crap in my head?
are there calcs like this on the real deal?

Usually such calculations are used for calculating the concentration of H+ and eventually the pH. This involves taking -log of x. To solve this quickly in your head don't simplify the 3rd root 4.5 x10^-8 all over 4. Write this as x=(4.5x10^-8 / 4)^(1/3)
Then, pH = - log (4.5x10^-8 / 4)^(1/3)
which implies pH = - (1/3) log (4.5x10^-8 / 4)
Just roughly divide the 4.5 with 4 (leaving the 10 ^-8 out) in your head and the answer you'll get will be a little more than 1. Do it on paper and you'll get 1.1
Now brin back the 10^-8
Therefore, the answer to 4.5x10^-8 / 4 = 1.1 x10^-8

the whole expression now looks like: - (1/3) log 1.1 x10^-8

Now you have to take the - log 1.1 x10^-8 which is equal to = 8 - log 1.1
Since the log of 1 is 0, the log of 1.1 can be assumed to be equal to 0 also.

Now the whole expression has simplified to pH = (1/3) x 8 = 8/3
This can easily be divided on paper and the answer would be 2.66.
Search for the answer closest to 2.66 in the answer choices.

I agree... without the log involved this would be difficult to do it in head.
but then again... you can always use graph theory for estimating this 😉 (courtesy of math minor).