- Joined
- Dec 27, 2009
- Messages
- 27
- Reaction score
- 0
because of the periodic nature of the orbit a simple relation between average ke is <k> of the companion star<u>. In particular, <k> =<u/2>.
For a circular orbit, the potential energy of the companion star is constant throughout the orbit. If the radius of the orbit doubles what happens to velocity?
To me u decrease to u/2 which equals to 1/2mv^2, so u/2 = 1/2mv^2. From this express can you infer that kinetic energy decreases by half? Also that the velocity would equal 1/ square of 2.
why would the potential not be u/4 since potential is halfed and if you plug in u/2/2 then you get a fourth of the potential?
For a circular orbit, the potential energy of the companion star is constant throughout the orbit. If the radius of the orbit doubles what happens to velocity?
To me u decrease to u/2 which equals to 1/2mv^2, so u/2 = 1/2mv^2. From this express can you infer that kinetic energy decreases by half? Also that the velocity would equal 1/ square of 2.
why would the potential not be u/4 since potential is halfed and if you plug in u/2/2 then you get a fourth of the potential?