log question

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spoog74

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can someone show me a quick and easy way to do this?


if a = log7B^7 then what is the value of 7^a?


Answer is b^7


Thanks !
 
It's just how you perform log functions, e.g. the definition of log.

x = log(base y)z

is defined as

y to the power of x = z

so log7b^7 = a is 7^a = b^7
 
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