Magnet, bar, work

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chiddler

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This is a question I struggled with a while ago and I do not remember how to prove it to myself:

There is a bar in a magnetic field. As an electron moves down the bar, work is done.

Why is there work in this case whereas a point charge in a Bfield will yield no work?
 
This is a question I struggled with a while ago and I do not remember how to prove it to myself:

There is a bar in a magnetic field. As an electron moves down the bar, work is done.

Why is there work in this case whereas a point charge in a Bfield will yield no work?

No work = magnetic force always perpendicular to velocity = UCM

Since the electron is not moving in a circle, its velocity is not always perpendicular to the MF and thus it does some work.
 
No work = magnetic force always perpendicular to velocity = UCM

Since the electron is not moving in a circle, its velocity is not always perpendicular to the MF and thus it does some work.

that was easy.

thank you lol
 
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