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- Nov 3, 2006
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cos 495= ???
i know that the reference angle would be 45 degrees. so then i thought cos 45 = 1/ sq root of 2 ( from a 45-45-90 triangle) but destroyers says cos 45 = sq root 2 / 2.
im confused
also.... is there a net of 32 or 34 ATP from the electron transport chain?
i know that the reference angle would be 45 degrees. so then i thought cos 45 = 1/ sq root of 2 ( from a 45-45-90 triangle) but destroyers says cos 45 = sq root 2 / 2.
im confused
also.... is there a net of 32 or 34 ATP from the electron transport chain?