Math Destroyer Q4...WTF

[egan]

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I might be just extremely clueless right now, but this problem just
seriously doesn't seem to make sense. Here it is:

4. The endpoints of the diagonal of a square are located at (2,4)
and (6,2). Find the area of the square.

A.4
B.20
C.10
D.36
E.rad 40

In the back they use the formula side(squared) + side(squared) = diagonal(squared) and find the diagonal through the distance formula.

However, a diagonal with endpoints at (2,4) and (6,2) can't form a
square right? One side would have length 4 and the other length 2.
I'm probably massively missing something stupid here but I just can't
figure it out

 

[LaughingGas]

the square is rotated about ~30 degrees counterclockwise.
Diagonal length= (2,4) ~(6,2) = (4^2 + 2^2) ^(1/2) = (16+4)^(1/2) => [5^(1/2)]*2
a^2+b^2=c^2
c^2= 20
a^2=b^2 ( a is side of square equal to b in the square..)
2*a^2 = 20
Area of square = side^2.
a^2= 10 = Area
Hope you get what I wrote..

 

[egan]

ahhhh, i get it. I knew there was something dumb I was forgetting.