Math destroyer question

Started by DocDoon
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DocDoon

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I have the newest edition of math destroyer and I'm having trouble with a problem. Problem 34 on test 7. I'm having trouble figuring out how to draw the right triangle to make 20 the base of the rhombus and the hypotenuse of the right triangle? If anyone could explain I would be very grateful.
 
I have the newest edition of math destroyer and I'm having trouble with a problem. Problem 34 on test 7. I'm having trouble figuring out how to draw the right triangle to make 20 the base of the rhombus and the hypotenuse of the right triangle? If anyone could explain I would be very grateful.
See the attached picture.
Once you draw the height, look at the triangle formed. It's a 30, 60, 90 triangle.
The altitude ( height) divides the base into 2 equal segments.
The height ( adjacent side to 30° angle) is given by: 10sqrt(3)
sdn.jpg