B BodybldgDoc Jan 17, 2007 #1 Advertisement - Members don't see this ad If the side length of a square is increased by 50%, the area increases by what percent? A. 125 B. 225 C. 25 D. 50 E. 75 please explain how to do this someone?
Advertisement - Members don't see this ad If the side length of a square is increased by 50%, the area increases by what percent? A. 125 B. 225 C. 25 D. 50 E. 75 please explain how to do this someone?
Ex_EE Full Member 10+ Year Member 15+ Year Member Joined Sep 23, 2006 Messages 338 Reaction score 0 Points 0 Location Houston Dental Student Jan 17, 2007 #2 You can just use an example such as 10 x 10 square 100 in area. Increased to 15 x 15 square = 225 area. So 125 % increase Upvote 0 Downvote
You can just use an example such as 10 x 10 square 100 in area. Increased to 15 x 15 square = 225 area. So 125 % increase
B BodybldgDoc Jan 17, 2007 #3 thanks a lot. i was thinking along the same lines but somehow my brain wasnt functioning early this morning. Upvote 0 Downvote
thanks a lot. i was thinking along the same lines but somehow my brain wasnt functioning early this morning.
S Streetwolf Ultra Senior Member Verified Member 10+ Year Member Dentist 15+ Year Member Joined Oct 25, 2006 Messages 1,801 Reaction score 7 Points 4,571 Location NJ Dentist Jan 17, 2007 #4 New_side = 1.5 * Old_side (New_side)^2 = (1.5 * Old_side)^2 = 2.25*Old_side^2 So the INCREASE is (2.25 - 1) / 1 = 1.25 ^ Without using an example such as 10 x 10. Upvote 0 Downvote
New_side = 1.5 * Old_side (New_side)^2 = (1.5 * Old_side)^2 = 2.25*Old_side^2 So the INCREASE is (2.25 - 1) / 1 = 1.25 ^ Without using an example such as 10 x 10.