Rock23 Member 10+ Year Member 15+ Year Member Joined May 18, 2006 Messages 41 Reaction score 0 Aug 16, 2006 #1 Members do not see this ad. can anyone show me how to solve this: sin(3x-26) = cos(5x-60), solve for x? (the answer is 22)
Members do not see this ad. can anyone show me how to solve this: sin(3x-26) = cos(5x-60), solve for x? (the answer is 22)
akdental Member 10+ Year Member 15+ Year Member Joined Aug 13, 2006 Messages 136 Reaction score 0 Aug 16, 2006 #2 http://mathforum.org/library/drmath/view/66858.html hope this helps.. Upvote 0 Downvote
keibee82 Blue_tooth... 15+ Year Member Joined May 9, 2006 Messages 477 Reaction score 2 Aug 16, 2006 #3 Rock23 said: can anyone show me how to solve this: sin(3x-26) = cos(5x-60), solve for x? (the answer is 22) Click to expand... in order to solve this problem, you first need to know that cos @ = sin (90-@) ; @ = theta so here you can just write above equation as 90-3x+26 = 5x - 60 x = 22 Upvote 0 Downvote
Rock23 said: can anyone show me how to solve this: sin(3x-26) = cos(5x-60), solve for x? (the answer is 22) Click to expand... in order to solve this problem, you first need to know that cos @ = sin (90-@) ; @ = theta so here you can just write above equation as 90-3x+26 = 5x - 60 x = 22
W wireless_doc Member 10+ Year Member 15+ Year Member Joined Jul 25, 2006 Messages 110 Reaction score 0 Aug 16, 2006 #4 keibee82 said: in order to solve this problem, you first need to know that cos @ = sin (90-@) ; @ = theta so here you can just write above equation as 90-3x+26 = 5x - 60 x = 22 Click to expand... What if 22 is not listed? What would you expect to see there? 😉 Upvote 0 Downvote
keibee82 said: in order to solve this problem, you first need to know that cos @ = sin (90-@) ; @ = theta so here you can just write above equation as 90-3x+26 = 5x - 60 x = 22 Click to expand... What if 22 is not listed? What would you expect to see there? 😉