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two cyclist start biking from a trials start 3 hrs apart. the 2nd cyclist travels at 10 miles per hour and starts three hrs after the first cyclist who is traveling at six miles per hour. how much time will pass before the second cyclist catches up with the the first from the time the second cyclist started biking?
a. two hrs
b. 4 1/2
c. 5 3/4
ans is B.
i get 5.6 hrs. basically what i did was 6t + 10(t-3)=60 ( i got a common divisible num. here)
so from here we get 16t =90 t=5.62
2. if steve can mix 20 drinks in five min. sue can mix twenty drinks in ten min. and jack can mix twenty drinks in fifteen mintues, how much time will it take all three of them working together to mix the twenty drinks?
ans. A how?
3. druing a five day festival, a number of visitors tripled each day. if the festival opened on a thur. with 345, what was the attendance on sunday? what is the fasted way to do this? multiplying is just a no brainer. anyone with a technique?
a. two hrs
b. 4 1/2
c. 5 3/4
ans is B.
i get 5.6 hrs. basically what i did was 6t + 10(t-3)=60 ( i got a common divisible num. here)
so from here we get 16t =90 t=5.62
2. if steve can mix 20 drinks in five min. sue can mix twenty drinks in ten min. and jack can mix twenty drinks in fifteen mintues, how much time will it take all three of them working together to mix the twenty drinks?
ans. A how?
3. druing a five day festival, a number of visitors tripled each day. if the festival opened on a thur. with 345, what was the attendance on sunday? what is the fasted way to do this? multiplying is just a no brainer. anyone with a technique?
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