Math Question

[Orgodox]

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What is n in terms of w and r if:
n/-r+w= w+r and w2-r2=6+r Where r is not equal to w?
Btw the bold 2s mean squared.

they say its r+6
I agree but another choice is (r-w)(r+w)
Isnt that more correct because they want the answer in terms of w and r a nd the choice they give gives the answer only in terms of r?

What I did was multiply they first equation on the left by -r+w to isolate n an d multiples the right side by -r+w which is (w+r)(-r+w). So that is = w2-r2 and they said then therefor n = 6+r but like I said does that answer the question?

 

[Streetwolf]

What is n in terms of w and r if:
n/-r+w= w+r and w2-r2=6+r Where r is not equal to w?
Btw the bold 2s mean squared.

they say its r+6
I agree but another choice is (r-w)(r+w)
Isnt that more correct because they want the answer in terms of w and r a nd the choice they give gives the answer only in terms of r?

What I did was multiply they first equation on the left by -r+w to isolate n an d multiples the right side by -r+w which is (w+r)(-r+w). So that is = w2-r2 and they said then therefor n = 6+r but like I said does that answer the question?

As long as you can find nothing more than either a w or an r (or both) in the answer it should be fine.

(r-w)(r+w) is wrong because it should be (w-r)(r+w).

 

[dleodyddlek]

as streetwolf have said,
(r+w)(r-w)= r^2 - w^2 isn't the same as (w+r)(-r+w)= w^2 - r^2 look closely :]