Math Question

Started by Dencology
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Dencology

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Hey guys, i have a hard time figuring this problem:

a construction firm receives an important contract and hires 15 temporary workers in addition to its full time staff. if the entire full time staff of 25 could complete the job in five months, and if temporary workers work 5/6 as fast as full time workers, how much time will be saved by hiring the additional workers?

ans. is 3 1/3. Would you show your work so i can follow?
 
Hey guys, i have a hard time figuring this problem:

a construction firm receives an important contract and hires 15 temporary workers in addition to its full time staff. if the entire full time staff of 25 could complete the job in five months, and if temporary workers work 5/6 as fast as full time workers, how much time will be saved by hiring the additional workers?

ans. is 3 1/3. Would you show your work so i can follow?
Full time staff finishes in 5 months. There are 25 of them. If there were 15 of them there would be 3/5 the help which means 5/3 the time = 25/3 months. Since the temporary workers work at 5/6 efficiency, it takes 6/5 the time = 10 months.

In one month the full time workers will do 1/5 the work. In one month the temporary workers will do 1/10 the work. Together that's 3/10 the work. To finish the job they'll need 3 and 1/3 months.

The time saved is 1 and 2/3 months, no? 3 and 1/3 is the time they'll work...