Math Question

[silveryhair]

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Can anyone explain how to do this problem?
I can't seem to picture what the diagram would like like.

If two sides of a Rhombus meet at a angle of 60 degrees and one of the sides of the length is 20, what is the area of the rhombus?

The answer is 200sq(3)

Thanks!

 

[hoylematt]

Hopefully that uploaded properly. As you can see a rhombus is just a square shifted over a little bit. The Formula is then B*H. if you drop a line directly down from the top corner splitting the base of 20, you can see that it forms a triangle (Red line). Following the rules for 30,60,90 triangles, the side opposite the 60 degree angle has to be 10sqrt(3) (i realized i put sqrt(2) on the figure sorry for the error) Either way, now that you know the base and the height you can solve for the area of the rhombus.

20*10sqrt(3) = 200sqrt(3)

 

[silveryhair]

Thanks! your awesome Hoylematt!

 

[hoylematt]

Yur Welcome! Yeah this problem confused me too, I kept imagining this skinny little rhombus like you play with when you are in elementary school. (turns out I was thinking about the diamond (white block) not the rhombus (Red block)) My wife, being an elementary school teacher, laughed and was sure to remind me that she knew that and I didn't.