math question

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

spoog74

Full Member
10+ Year Member
Joined
Jan 31, 2011
Messages
423
Reaction score
0
what value of x satisfies this inequality

x^2-6x+8 < 0

Isnt it (x-4) (x-2) < 0

Thus, it would be x <4 and x < 2?

The answer says its 2 < x < 4 .. which i dont get
 
x^2 - 6x + 8 < 0
(x-4) (x-2) < 0

In order for this to hold true one of the values must be (+) while the other is (-)
(+) (-) < 0
(-) (+) < 0

A. x - 4 > 0 and x - 2 < 0
or
B. x -4 < 0 and x -2 > 0

In A: x > 4 and x < 2 [This is impossible so this combination is not an option]

In B: x < 4 and x > 2 thus 2 < x < 4
 
what value of x satisfies this inequality

x^2-6x+8 < 0

Isnt it (x-4) (x-2) < 0

Thus, it would be x <4 and x < 2?

The answer says its 2 < x < 4 .. which i dont get

This is the exact question that was on the Quantitative Reasoning of the Kaplan Diagnostic DAT so here is their explanation word for word: The question for the similar problem was: " If x^2-9<0, which of the following is true?"

If x^2-9<0, then x^2<9. If x^2<9 and x is positive, then x<3. If x^2<9 and x is negative, then x>-3. So it must be true that -3<x<3.

It is good to remember that x^2<T is equivalent to -sqrtT<x<sqrtT if T is a positive number. This would be applicable in this question, where x^2<9 is equivalent to -sqrt9<x<sqrt9, or -3<x<3.

It is also good to remember that x^2>T is equivalent to x>sqrtT or x<-sqrtT if T is a positive number
 
This is the exact question that was on the Quantitative Reasoning of the Kaplan Diagnostic DAT so here is their explanation word for word: The question for the similar problem was: " If x^2-9<0, which of the following is true?"

If x^2-9<0, then x^2<9. If x^2<9 and x is positive, then x<3. If x^2<9 and x is negative, then x>-3. So it must be true that -3<x<3.

It is good to remember that x^2<T is equivalent to -sqrtT<x<sqrtT if T is a positive number. This would be applicable in this question, where x^2<9 is equivalent to -sqrt9<x<sqrt9, or -3<x<3.

It is also good to remember that x^2>T is equivalent to x>sqrtT or x<-sqrtT if T is a positive number



tooth, while i appreciate your effort in trying to explain the problem but i have no clue what you just wrote lol. So basically in the inequality such as these, one is the opposite of the other one, but it doesnt matter which one?
 
Top