math

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

vvvv

Full Member
10+ Year Member
15+ Year Member
Joined
May 12, 2007
Messages
119
Reaction score
0
I dont really understand what the question asking for, can someone helps me plz.
Due to copy right i have to delete the question but it's question # 67 in math section of Orgo. (4/21 edition).

a.2
b.3
c.4
d.5
e.6

answer is 6
I get confused with the rum, alcohol, drink.....cant tell the different
 
I dont really understand what the question asking for, can someone helps me plz.
Mix 4 oz. of rum with a certain quantity of cola. The rum is 40% alcohol by volume. if the drink is to be 16% alcohol by volume, how much cola is needed?


a.2
b.3
c.4
d.5
e.6

answer is 6
I get confused with the rum, alcohol, drink.....cant tell the different

Is this a serious question? it involves alcohol so I'm a bit wary... but...

I believe it is like a dilution problem (gen chem) where M1V1=M2V2, where M1 (rum)=.4, V1 (rum)=4oz, M2 (total)=.16, and V2=the total volume of the liquid.

If you stick in the numbers for the variables the total volume of the drink will end up being 10 oz, so this is the total volume of rum and coke needed for the percentage to be 16%. Subtract this from the volume of rum and you get the volume of the coke (10-4=6). So 6 is your answer.

And if you went to the right colleges you should know this without the calculations 😉
 
After spending 10 min on this problem, I have a feeling that this is Gen Chem question rather than math question.
I used CV = CV method. The first CV is before mixing, and the second CV is after mixing.
This equation is used for volume and concentration and maybe it's not a proper method but it worked so let me share it with you. Now is 2:40am so there is a high chance that i am still dreaming.

CV= CV
concentration of alcohol = 0.4 since it's 4 %
volume of rum = 4oz
after mixing the rum with cola, volume of mixture = ?
concentration of alcohole = 0.16 since it's 16%
Therefore,
(0.4)(4) = (0.16)X
(0.4)(4)/(0.16) = X
X = 10
since the mixture has 10oz and we already know that 4 oz out of 10oz is rum,
and we are looking for the volume of cola, you subtract 4 from 10 to get the volume
of cola which is 6.

Edit: woot....Shjfr answered it 1 min before i did. 🙂

I don't know if this can really be the math problem. People in math class will struggle with this type of problems
unless they took GenChem.
 
Top