Minimum voltage in redox titration?

[fluoropHore]

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if you add an anion (titrant) to a cation at the cathode in soln, they precipitate out, according to one passage. since you are taking away cation from the cathode, you are effectively dropping the voltage (less reactant available to be reduced at the electrode).

Why is answer B not better than answer D for this then?
The observed voltage reaches a min when:
a. [cation]init > [titrant anion]added
b. [cation]init = [titrant anion]added
c. mL 0.1M cation int > mL 0.1M titrant added
d. ml 0.1M cation int = mL 0.1M titrant added

equivalence point = mol cation int= mol irtant added (assuming 1:1)
isnt B & D saying the same thing?
Errr.. I know it's not.

 

[syoung]

Well you could have this for B:
conc init = 5 mol / 100 mL and titrant could be 20 mol / 100 mL but you just said you added concentrations in and not volume
when you titrate you add a certain amount of vol (drops) of a known conc of titrant
so D is talking about the vol of the same conc of cation = vol of same conc titrant added
your equivalence point is valid.