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This is problem 231 in 2010 destroyer. Take a look at it and tell me what you think.
The solution gives the example of
(.120)V1 = (.20)(60)
.120V1 = 1.20
V1 = 10
isn't .20 x 60 = 12... not 1.20
so V1 = 100
the half equivalence point should be 50.
The solution gives the example of
(.120)V1 = (.20)(60)
.120V1 = 1.20
V1 = 10
isn't .20 x 60 = 12... not 1.20
so V1 = 100
the half equivalence point should be 50.