Mole fraction

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

anteater85

Full Member
10+ Year Member
Joined
Jul 2, 2009
Messages
84
Reaction score
1
Hi guys could u plz help me with this question:

The molecular weight of ethyl alcohol is 46, and MW of water is 18. How many grams of ethyl alcohol must be mixed with 100 mL of water for the mole fraction(X) of ethyl alcohol to be 0.2?

THe answer is 64.4g

Thank you

Members don't see this ad.
 
Density of H2O = 1 g/ml
100ml H2O x (1g/1ml) x (1mole/18g) = 5.6 mole H2O

Mole fraction = n(alc)/n(total) = n(alc)/(5.6 + n(alc)) = 0.2

1.12 + 0.2n(alc) = n(alc)

0.8n(alc) = 1.12 --> n(alc) = 1.4 mole

1.4 mole x (46g/1mole) = 64.4g
 
Density of H2O = 1 g/ml
100ml H2O x (1g/1ml) x (1mole/18g) = 5.6 mole H2O

Mole fraction = n(alc)/n(total) = n(alc)/(5.6 + n(alc)) = 0.2

1.12 + 0.2n(alc) = n(alc)

0.8n(alc) = 1.12 --> n(alc) = 1.4 mole

1.4 mole x (46g/1mole) = 64.4g

where did u get the 1.12 from?
 
Top