n+1 n-1 failure in anaphase question

[510586]

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• A homologous chromosomal pair fails to separate during meiosis 1 of anaphase. The resulting cells would be...
1) N-1, n-1, n+1,n+1
2) N+1, n-1, n, n
3) N, n, n, n+1
4) N-1, n-1, n, n
5) N+1, n+1, 2n, 2n
I understand how to get to the right answer for these types of questions, but I wanted to ask: do we always assume there are 2 homologous pairs to start with? (like 2 homologous pairs each with 2 chromosomes each with 2 chromatids)

 

[RuffDay]

Since this question states that it is in meiosis 1 of anaphase, you can assume that it went through prophase I. Remember the unique characteristics of prophase I: recombination, homologous chromosomes, and tetrads.

The key is the tetrads in this case.

 

[510586]

Since this question states that it is in meiosis 1 of anaphase, you can assume that it went through prophase I. Remember the unique characteristics of prophase I: recombination, homologous chromosomes, and tetrads.

The key is the tetrads in this case.

I meant to say how do we know it is 2 though? by the answer choices? Would it ever be like 1 tetrad or 3 tetrads?

 

[dancer17]

what was the answer for this?

 

[510586]

what was the answer for this?

No real consensus. Pretty sure homologues can be in many pairs not just 2, but maybe we judge by the answer choices.