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net torque question

Discussion in 'MCAT Study Question Q&A' started by ssiding, Dec 18, 2008.

  1. ssiding

    2+ Year Member

    Aug 20, 2008
    Likes Received:
    A rectangle book weighing 20N with sides of 10cm and 20cm is placed on a horizontal table. Using each of your hands, you exert forces of 10N each in opposite directions at opposite corners, such that you are pushing parallel to the shorter side in each case. What net torque are ou providing to the book?

    A. 0 N-m
    B. 0.5 N-M
    C. 1 N-m
    D. 2 N-m
  2. TieuBachHo

    7+ Year Member

    Jul 23, 2008
    Likes Received:
    Torgue = r F sin(angle of F and r)

    Use trig. to find r = 5 x squr(5) cm ... sine = 2/squr(5) ... So Torgue = 100 N.cm = 1 N.m ... Net torque = 2 x torques = 2 N.m ... So answer is D ... double check your with ur answer. I think they bluff you with the weigh of the book since it's rested on the table. This problem is straight forward.

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