Nice Chemistry Question

[heshyn2000]

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An aqueous solution of HNO3 has a PH of 2.30 what will be the new PH if 10 mL. of this solution is diluted by 30 mL. of H2O ?

 

[dat_student]

An aqueous solution of HNO3 has a PH of 2.30 what will be the new PH if 10 mL. of this solution is diluted by 30 mL. of H2O ?

pH = 2.9

 

[dentalengineer]

PH= -log[H+]
2.3 = -log[H+]
[H+] = .005

N1V1= N2V2 (N=M Monoprotic)
.005 * 10 = N2 * 40
N2=M2= .00125

New PH= -log .00125
PH= 2.9

 

[joonkimdds]

PH= -log[H+]
2.3 = -log[H+]
[H+] = .005

N1V1= N2V2 (N=M Monoprotic)
.005 * 10 = N2 * 40
N2=M2= .00125

New PH= -log .00125
PH= 2.9

where is 0.005 from?

 

[heshyn2000]

where is 0.005 from?

2.3 is the -log of .005 or 5X10 -3

 

[Flipper405]

PH= -log[H+]
2.3 = -log[H+]
[H+] = .005

N1V1= N2V2 (N=M Monoprotic)
.005 * 10 = N2 * 40
N2=M2= .00125

New PH= -log .00125
PH= 2.9

Thanks. Explanations are quite useful.