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Ok we know that the power of a light bulb would be
P= I (current of bulb) x V (voltage of bulb)
But that would be in an ideal situation. What sorts of factors would contribute to a real messurement of the power of a light bulb being less than the ideal power of the light bulb in this calculation?
Thanks!
P= I (current of bulb) x V (voltage of bulb)
But that would be in an ideal situation. What sorts of factors would contribute to a real messurement of the power of a light bulb being less than the ideal power of the light bulb in this calculation?
Thanks!