• The site has been updated!

    If you see any bugs, please report them in this thread.

Nonideal situations of a lightbulb

byeh2004

Senior Member
10+ Year Member
5+ Year Member
Mar 31, 2005
604
0
0
Status (Visible)
Ok we know that the power of a light bulb would be

P= I (current of bulb) x V (voltage of bulb)

But that would be in an ideal situation. What sorts of factors would contribute to a real messurement of the power of a light bulb being less than the ideal power of the light bulb in this calculation?

Thanks!
 

mc4435

Full Member
10+ Year Member
Oct 7, 2006
325
1
201
Status (Visible)
  1. Pre-Medical
Some of the electrical energy going through the lightbulb (as current) is dissipated as heat and light, so the energy going out of the bulb is less than what goes in. Because power is in units of Joules/second, if the joules decreases under "real" conditions, then the power is less than ideal conditions as well.
 
This thread is more than 14 years old.

Your message may be considered spam for the following reasons:

  1. Your new thread title is very short, and likely is unhelpful.
  2. Your reply is very short and likely does not add anything to the thread.
  3. Your reply is very long and likely does not add anything to the thread.
  4. It is very likely that it does not need any further discussion and thus bumping it serves no purpose.
  5. Your message is mostly quotes or spoilers.
  6. Your reply has occurred very quickly after a previous reply and likely does not add anything to the thread.
  7. This thread is locked.