T The_Juggernaut New Member 15+ Year Member Joined Jun 6, 2007 Messages 8 Reaction score 1 Points 4,716 Post Doc May 27, 2021 #1 Members do not see this ad. I got this question correct but not sure why. Appreciate it if anybody can walk me through it. Thanks!
Members do not see this ad. I got this question correct but not sure why. Appreciate it if anybody can walk me through it. Thanks!
D deleted1077312 May 28, 2021 #2 You get the half life from the graph, then how many times do you divide 56/2 to get 14. Twice, multiply that times the half life you got and that’s the answer Upvote 0 Downvote
You get the half life from the graph, then how many times do you divide 56/2 to get 14. Twice, multiply that times the half life you got and that’s the answer
T The_Juggernaut New Member 15+ Year Member Joined Jun 6, 2007 Messages 8 Reaction score 1 Points 4,716 Post Doc May 28, 2021 #3 Thanks! Upvote 0 Downvote
B BerkReviewTeach Company Rep for now-defunct Course & Bad Singer Verified Member Vendor 15+ Year Member Joined May 25, 2007 Messages 4,119 Reaction score 962 Points 5,606 Jul 24, 2022 #4 This is a first order plot, where the half life is constant. If you look at the graph, 100% is at t=0, 50% is around t=53, 25% is around t=106, etc... So the easy way to set this up is to say that 56 —> 28 —> 14, meaning it is cut in half TWICE. That requires two half lives, which is 2 x 53 = 106. I hope this helps. Upvote 0 Downvote
This is a first order plot, where the half life is constant. If you look at the graph, 100% is at t=0, 50% is around t=53, 25% is around t=106, etc... So the easy way to set this up is to say that 56 —> 28 —> 14, meaning it is cut in half TWICE. That requires two half lives, which is 2 x 53 = 106. I hope this helps.