Number of glucose molecules?

[soby10]

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This is from TPR biology drill questions.

In terms of ATP, approximately how many glucose molecules would it take to translate a 60 amino acid polypeptide chain in a eukaryote undergoing aerobic respiration?

A.6
B.8
C.10
D.12

Answer is 8. How do you find it? Please clearly state how the answer is found. Thanks.

 

[pfaction]

4n-1 = # ATP used.
60*2 = 120 to make TRNA's
1 to combine the ribosome
1 for each binding
1 for each translocation
120+1+59+59 = 239
aerobic respiration = 32 AA
240/30 = 8
****YEAHOMGIGOTITRIGHT *had to double check myself on TPR to make sure it was 4N-1 or 4n+1

 

[SaintJude]

You mean princeton asks you to know how many ATP it takes to make one chain? I'm sorry, but I don't think this "4n-1" value is something AAMC asks us to know. If you needed it, it would be given in a passage

 

[411309]

they asked this in one of their TPR passages on bio, tough question. Doesnt hurt to know 4n-1 tells you the number of high energy phosphate bonds.

 

[pfaction]

they asked this in one of their TPR passages on bio, tough question. Doesnt hurt to know 4n-1 tells you the number of high energy phosphate bonds.

They also asked for total # of ATP from fatty acids, I was like fuuuuu. Was one off, answer choice was like 200,201, 20# FFFFF

 

[mcloaf]

you mean princeton asks you to know how many atp it takes to make one chain? I'm sorry, but i don't think this "4n-1" value is something aamc asks us to know. If you needed it, it would be given in a passage

qft.

 

[soby10]

Thanks makes sense. Actually it was in a free standing question so I had no clue how to answer it.

 

[MedPR]

What is this 4n-1 business? I've never heard of it.

 

[pfaction]

What is this 4n-1 business? I've never heard of it.

Check out my math. n = # amino acid.

 

[MedPR]

4n-1 = # ATP used.
60*2 = 120 to make TRNA's
1 to combine the ribosome
1 for each binding
1 for each translocation
120+1+59+59 = 239
aerobic respiration = 32 AA
240/30 = 8
****YEAHOMGIGOTITRIGHT *had to double check myself on TPR to make sure it was 4N-1 or 4n+1

Check out my math. n = # amino acid.

Thanks. So even though aerobic respiration is typically considered to have 36-38 net ATP, it wouldn't really make a difference for this question because 239/38 is still more than 6. So the answer is about 7, so closest is 8.

 

[pfaction]

TPR says aerobic eukaryotic makes 30 ATP/glucose and prokaryotes make 32 (so I miswrote but did math right?) due to euk needing to transport NADH from cytosol to interior. But I divided it right lol. Yeah the real thing is like what, 7.8 or something.

 

[gettheleadout]

TPR says aerobic eukaryotic makes 30 ATP/glucose and prokaryotes make 32 (so I miswrote but did math right?) due to euk needing to transport NADH from cytosol to interior. But I divided it right lol. Yeah the real thing is like what, 7.8 or something.

Bumping this because the # ATP = 4n -1 is an interesting equation, but also because I don't understand where TPR is getting their ATP yields for aerobic respiration.

I understand that there is variability in the glycolytically-derived NADH yielding either 2 or 3 net ATP through oxidative phosphorylation (due to transport of the NADH into the mitochondria), but that just means that prokaryotes should have a maximum yield bonus of +2 over eukaryotes. EK, TBR, and several other sources I trust tally the eukaryotic cellular respiration output at 36-38 ATP per glucose, where 38 would be the prokaryotic yield.

Yes, I realize there is real-world variability in the ATP yield per coenzyme, but that's not something we can be expected to know the consensus on for the exam, it would be given in a passage if they wanted us to use a non-standard value. So my question is, why do TPR's numbers disagree with everything else? How are they rationalizing 30-32 ATP per glucose?