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OCHEM clarification

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FCMike11

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Finished reading the OCHEM TBR chapter yesterday. I was having trouble understanding the bold part of this word-for-word phrase in the book

Pg 134 very first sentence (it may be different for you since the versions of TBR vary a little)
"Whenever you see a doublet and a septet in a 6 :1 ratio, you should conclude
that there is an isolated isopropyl group ((H3Q2CH-) somewhere in the
molecule."

EDIT: I think I got it. I believe what it means is that is a 6 hydrogen:1 hydrogen ratio. Can someone just confirm this for me?:)

You are right---its ch-ch3
ch3
Hard to draw but both ch3s are coming off of your ch. Those 6 hydrogen are splitting it into a scepter (split by six). With a 6 to 1 ratio.
 
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