Last edited:
OCHEM clarification
- Thread starter pepocho
- Start date
- Joined
- Aug 24, 2011
- Messages
- 1,134
- Reaction score
- 773
Finished reading the OCHEM TBR chapter yesterday. I was having trouble understanding the bold part of this word-for-word phrase in the book
Pg 134 very first sentence (it may be different for you since the versions of TBR vary a little)
"Whenever you see a doublet and a septet in a 6 :1 ratio, you should conclude
that there is an isolated isopropyl group ((H3Q2CH-) somewhere in the
molecule."
EDIT: I think I got it. I believe what it means is that is a 6 hydrogen:1 hydrogen ratio. Can someone just confirm this for me?
You are right---its ch-ch3
ch3
Hard to draw but both ch3s are coming off of your ch. Those 6 hydrogen are splitting it into a scepter (split by six). With a 6 to 1 ratio.
