Dencology

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Mar 7, 2008
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please look at question 138(Ochem) destroyer,

why answer is B. it should be C, because internal alkene is more stable that terminal alkene. so when OH leaves the double bond should be forming in the middle and not at the terminal.
 

Danny289

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Dec 2, 2006
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please look at question 138(Ochem) destroyer,

why answer is B. it should be C, because internal alkene is more stable that terminal alkene. so when OH leaves the double bond should be forming in the middle and not at the terminal.
it is E2 RXN and the rule is this:
small base gives most substituted Alkene( internal), Bulky base gives least substituted( in this case terminal)
(CH3)3COOK is bulky base. hope it helped.
 
OP
D

Dencology

10+ Year Member
Mar 7, 2008
396
0
Status
Pre-Dental
it is E2 RXN and the rule is this:
small base gives most substituted Alkene( internal), Bulky base gives least substituted( in this case terminal)
(CH3)3COOK is bulky base. hope it helped.

all right. thanks.