1-methylcyclohexane treated with Br2 and hv gives 1-bromo, 1-methyl cyclohexane. This is what the destroyer says. Now shouldn't the methyl group be an o/p activator and make it either 1-bromo,2-methylcyclohexane or 1-Bromo,4-methyl cyclohexane?
1-methylcyclohexane treated with Br2 and hv gives 1-bromo, 1-methyl cyclohexane. This is what the destroyer says. Now shouldn't the methyl group be an o/p activator and make it either 1-bromo,2-methylcyclohexane or 1-Bromo,4-methyl cyclohexane?
Two things, firstly O/P activation is only by benzene not by cyclohexane. Secondly Br/Hv wouldnt add to benzene anyways it would add in the benzylic position. But you dont even have a benzene.
1-methylcyclohexane treated with Br2 and hv gives 1-bromo, 1-methyl cyclohexane. This is what the destroyer says. Now shouldn't the methyl group be an o/p activator and make it either 1-bromo,2-methylcyclohexane or 1-Bromo,4-methyl cyclohexane?