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Hello everyone, I have a question that I was sure I was right on but Topscore said I was wrong. On Ochem test #3 it asks an NMR question along the lines of "which one of these will show only one resonance peak in the NMR spectrum?"
and it has
a. Benzene with two Bromines at opposite ends.
b. CH3-C(triple bond)N
c. CH3-0-CH3
d. Two of the above
e. All the above
Di-substituted benzene would show 2 equivalent doublets, and would therefore disqualify it. b would show a 3H singlet and c would show a 6H sinlget. I said the answer was d, but Topscore said it was e. Would someone enlighten me please?
and it has
a. Benzene with two Bromines at opposite ends.
b. CH3-C(triple bond)N
c. CH3-0-CH3
d. Two of the above
e. All the above
Di-substituted benzene would show 2 equivalent doublets, and would therefore disqualify it. b would show a 3H singlet and c would show a 6H sinlget. I said the answer was d, but Topscore said it was e. Would someone enlighten me please?
