oChem Question

[passDAThope]

---

Members don't see this ad.

Just took the Barron's practice test and I had three questions:

1) What is the orientation of the bond between two sp2 hybridized carbons in relation to the orientation of its pi bond.

I thought the answer was perpendicular but it's parallel. Is because the actual bond is parallel but the orbitals are what's perpendicular?

2) How many isomers are exist for the following aldehyde: O=CH-HCOH-HCOH-HHCOH

Its four because there are only two chiral carbons, right?

3) What are the Hybridizations of the C and N atom in CN- ion are:
I believe its sp and sp2, respectively.

Your response is greatly appreciated.

 

[predentn]

Just took the Barron's practice test and I had three questions:

1) What is the orientation of the bond between two sp2 hybridized carbons in relation to the orientation of its pi bond.

I thought the answer was perpendicular but it's parallel. Is because the actual bond is parallel but the orbitals are what's perpendicular?

2) How many isomers are exist for the following aldehyde: O=CH-HCOH-HCOH-HHCOH

Its four because there are only two chiral carbons, right?

3) What are the Hybridizations of the C and N atom in CN- ion are:
I believe its sp and sp2, respectively.

Your response is greatly appreciated.

How do you figure sp2 for N in CN-? Draw out the Lewis structure.

 

[passDAThope]

How do you figure sp2 for N in CN-? Draw out the Lewis structure.

For some reason I was thinking the Nitrogen had the extra lone pair. Well wouldn't that make them both sp (C and N)?

 

[Mstoothlady2012]

both sp

 

[predentn]

For some reason I was thinking the Nitrogen had the extra lone pair. Well wouldn't that make them both sp (C and N)?

Yes, but they both have a lone pair.

 

[Flipper405]

Just took the Barron's practice test and I had three questions:

1) What is the orientation of the bond between two sp2 hybridized carbons in relation to the orientation of its pi bond.

I thought the answer was perpendicular but it's parallel. Is because the actual bond is parallel but the orbitals are what's perpendicular?

I think they're referring to the sigma bond between the carbons, which is in fact parallel to the pi bond. The sigma bond is directly between the two carbons, while the pi bond is comprised of sections "above" and "below" the sigma bond.