R Riro New Member 10+ Year Member Joined Nov 25, 2009 Messages 1 Reaction score 0 Points 0 Pre-Dental Nov 25, 2009 #1 Advertisement - Members don't see this ad I have a question about forming alkenes. When you add NaOC2H5 to 1-Bromoethyl Benzene, how come you get a double bond between the 2 carbons on the ethyl side chain?
Advertisement - Members don't see this ad I have a question about forming alkenes. When you add NaOC2H5 to 1-Bromoethyl Benzene, how come you get a double bond between the 2 carbons on the ethyl side chain?
W wantVCUdental Full Member 10+ Year Member Joined Aug 6, 2009 Messages 982 Reaction score 1 Points 4,531 Pre-Dental Nov 25, 2009 #2 Riro said: I have a question about forming alkenes. When you add NaOC2H5 to 1-Bromoethyl Benzene, how come you get a double bond between the 2 carbons on the ethyl side chain? Click to expand... This is a simple E2 reaction, and the double bond can't fall on to carbon in the benzene ring, because a carbon can only have 2 bonds Upvote 0 Downvote
Riro said: I have a question about forming alkenes. When you add NaOC2H5 to 1-Bromoethyl Benzene, how come you get a double bond between the 2 carbons on the ethyl side chain? Click to expand... This is a simple E2 reaction, and the double bond can't fall on to carbon in the benzene ring, because a carbon can only have 2 bonds
