The fastest way to solve this problem is to know that a convex mirror and concave lens will have virtual, upright and reduced.
I just wanted to confirm this with calculations.
(1/-30)=(1/12)+(1/i) (focal length is -, because of convex mirror)
m=-i/o=8/12=0.66 <---- m=+ indicates upright=virtual, Since m is <1 it is reduced.
Is this the correct way of calculating this or do I put a negative in front of the do?