orbital chemistry

[oreoeater82]

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one more question... this time about orbital chemistry!

1,3 - butadiene has 4 conjugated carbons. what does that mean and how do we use that info to deduce that there are 4 pi electrons... i think i understand hybridization... each of the carbons of 1,3-butadiene are sp2 hybridized... right?

After i understand that... how do i find electrons in the ground state? and how do i know which orbitals they will occupy?

thanks for your reply everyone!😀

 

[Danny289]

one more question... this time about orbital chemistry!

1,3 - butadiene has 4 conjugated carbons. what does that mean and how do we use that info to deduce that there are 4 pi electrons... i think i understand hybridization... each of the carbons of 1,3-butadiene are sp2 hybridized... right?

After i understand that... how do i find electrons in the ground state? and how do i know which orbitals they will occupy?

thanks for your reply everyone!😀

don't worry about that. Just know how many Pi and sigma bounds you have and hybridization of each carbon. 👍

 

[cyrano]

C=C-C=C

Each of the carbons share a sigma bond (single bond), however only carbons 1 and 2 as well as carbons 3 and 4 share a pi bond (double bond). Whenever you have multiple bonds between carbons (double and triple bonds) there is an initial sigma bond and then the second and third bond are comprised of pi bonds. Pi bonds are formed by the Px, Py, and Pz orbitals. That's why when you have a double bonded carbon it's hydridization drops from sp3 to sp2+p. It needs that extra P orbital available for pi bonding.
Here's a pic:
http://mcdb.colorado.edu/courses/3280/images/photoreception/bond4.gif

Hope this helps.

 

[oreoeater82]

thanks... very much appreciated!🙂