hannah999 Full Member 10+ Year Member 15+ Year Member Jul 14, 2008 #1 Advertisement - Members don't see this ad Can someone please explain to me why Glycine would need two equivalents of base to be completely neutralized. H2NCH2CO2H + -OH --> H2NCH2COO- how does the second base work? Last edited: Jul 14, 2008
Advertisement - Members don't see this ad Can someone please explain to me why Glycine would need two equivalents of base to be completely neutralized. H2NCH2CO2H + -OH --> H2NCH2COO- how does the second base work?
doc3232 Full Member 10+ Year Member 15+ Year Member Jul 14, 2008 #2 Sure, it is because a fully protonated glycine would have NH3+ and COOH to neutralize. That would need two OH- to be neutralized. Upvote 0 Downvote
Sure, it is because a fully protonated glycine would have NH3+ and COOH to neutralize. That would need two OH- to be neutralized.
osimsDDS Full Member 10+ Year Member 5+ Year Member 15+ Year Member Jul 14, 2008 #3 Only when glycine is in acidic pH it will need 2 moles of base to be fully neutralized... Because when glycine is acidic it is like this: NH3+CH2COOH When glycine is basic it is like this: NH2CH2COO- And physiological pH (pH=7) it is like this: NH3+CH2COO- Upvote 0 Downvote
Only when glycine is in acidic pH it will need 2 moles of base to be fully neutralized... Because when glycine is acidic it is like this: NH3+CH2COOH When glycine is basic it is like this: NH2CH2COO- And physiological pH (pH=7) it is like this: NH3+CH2COO-