Orgo Destroyer #33

[motivated dent]

Advertisement - Members don't see this ad

can someone explain why A is optically inactive? it's not a meso compound right? and why does B only have a one enantiomer when they aren't mirror images?

 

[Sublimation]

can someone explain why A is optically inactive? it's not a meso compound right? and why does B only have a one enantiomer when they aren't mirror images?

I dont have destroyer. if you post the question i can be of more help. 🙂

 

[jalpari02]

A is not optically active because when it goes through the bromination reaction, it does not produce any chiral centers. one bromine is attached to a CH2, the other is attached to a carbon attached to 2 other CH2s (Br - C(CH2)).

B is not the answer either because it only has one chiral center, thus leading to only one enantiomer. diastereomers usually have two chiral centers that have different configurations.

 

[dg7903]

I have destroyer and #33 on mine is "Arrange the following compounds in order of decreasing reactivity in the E2 mechanism?"
Can anyone clear this out? I'm confused...