oxidation numbers

[bigdog8829]

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[xoangelxo]

What would be the oxidation number for each of the atoms in these molecules and how did u figure it out?.... 3H2SO4 ---> Al2(SO4)3 Thanks.

 

[Danny289]

What would be the oxidation number for each of the atoms in these molecules and how did u figure it out?.... 3H2SO4 ---> Al2(SO4)3 Thanks.

1- for: H2SO4

H= +1 "H" always +1 (exep -1 in metal halid)
S= +6
O= -2 "O" alway -2(exept -1 in peroxides and +2 in presents F)



now you can find S if you want 🙂 ( ignore multipy *3* for your calcolation)
(2x (+1) )+ S + (-2 x 4) = 0 =====> S= +6


2- for: Al2(SO4)3

Al= +3 "Al" always +3
O= -2 we already talked about "O"
S= +6 "S" is same becouse we have same SO4^-2 as above but we can calculate :

[2 x (+3)]+ 3[(S+(-2 x4)] = 0
S= +6



important attention : when you are calculatinn oxidation numbers DO NOT CONSIDER MULTPY NUMBER. in above example 3 for H2SO4 and pay attention I consider 3 in prouduct because it is not multipy No, it is a part of your Molecule(Al2(SO4)3 is a moecule 3 (SO4) is a part of
Al2(SO4)3)
hopefully it helped !

 

[xoangelxo]

thanks! =)