Oxidation state question

[apoptosis123]

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The gist of this question is the reaction between a rhodium catalyst and hydrogen gas:

Rh(Ph3P)Cl + H2 --> Rh(Ph3P)H2Cl

The answer explanation is saying that Rh's oxidation state increases from +1 to +3, which I don't see. It sates that the Ph3P group is uncharged, which I already assumed. It also says that H has an oxidation of 1, which I also already knew. With that in mind, I can see how Rh would have a +1 charge in the reactant, but it seems like it would have a -1 charge in the product.

 

[nuD]

There's several ways to approach these questions, but this is the way I do it.

Rh(Ph3P)Cl: Cl- is -1. Ph3P is 0. So Rh is +1.

Rh(Ph3P)H2Cl: Cl- is -1. H- is -1 (x2 = -2). So Rh is +3.