oxidation #

[madame99]

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In the equation:

AgBr (s) + 2S2O3^2- (aq) ---> Ag (S2O3)2 ^3- (aq) + Br- (aq)

how the oxidation state of Ag changes?

On the reactant side Ag is +1 since Br is -1 and its a solid, but for the product side I tried to work it out by adding the oxi state of oxygen (6 * -2) and S (-2 *4) for a total of -20, since the total charge is of the molecule is -3 it would make Ag would be +17 but thats obviously not right...then i thought maybe Ag could be +2 since the subscript of S2O3 is 2 but that wasnt right either...the correct answer is +1, any ideas as to why?

 

[TieuBachHo]

In the equation:

AgBr (s) + 2S2O3^2- (aq) ---> Ag (S2O3)2 ^3- (aq) + Br- (aq)

how the oxidation state of Ag changes?

On the reactant side Ag is +1 since Br is -1 and its a solid, but for the product side I tried to work it out by adding the oxi state of oxygen (6 * -2) and S (-2 *4) for a total of -20, since the total charge is of the molecule is -3 it would make Ag would be +17 but thats obviously not right...then i thought maybe Ag could be +2 since the subscript of S2O3 is 2 but that wasnt right either...the correct answer is +1, any ideas as to why?

OK, the group thiosulfate has an oxidation of -2 and 2 of it is -4 ... The overall compound has an ox. of -3 ... Then obviously Ag must be +1 to balance it ... -4+1 = -3

 

[ballofnerves]

In the equation:

AgBr (s) + 2S2O3^2- (aq) ---> Ag (S2O3)2 ^3- (aq) + Br- (aq)

how the oxidation state of Ag changes?

On the reactant side Ag is +1 since Br is -1 and its a solid, but for the product side I tried to work it out by adding the oxi state of oxygen (6 * -2) and S (-2 *4) for a total of -20, since the total charge is of the molecule is -3 it would make Ag would be +17 but thats obviously not right...then i thought maybe Ag could be +2 since the subscript of S2O3 is 2 but that wasnt right either...the correct answer is +1, any ideas as to why?

This isn't a reduction-oxidation reaction. It is just a simple single displacement reaction, so the oxidation numbers all remain the same.

 

[madame99]

This isn't a reduction-oxidation reaction. It is just a simple single displacement reaction, so the oxidation numbers all remain the same.

Ohhh that makes so much more sense now, thank you 🙂