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Oxygen momentum
Started by COYspurs
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Let's see.
In a bottle, hydrogen gas and oxygen gas molecules should have the same average kinetic energy (KE)
where p = momentum, m = mass of a gas molecule, and v = (rms) velocity.
Since the average kinetic energies should be equal for H and O:
the sub O's and H's stand for oxygen and hydrogen.
The 2's cancel out.
Also, oxygen gas has a mass of 32 amu. Hydrogen gas has a mass of 2 amu. Thus,
The momentum of oxygen gas is on average 1/4 of that of hydrogen gas (if my calculations are correct).
In a bottle, hydrogen gas and oxygen gas molecules should have the same average kinetic energy (KE)
where p = momentum, m = mass of a gas molecule, and v = (rms) velocity.
Since the average kinetic energies should be equal for H and O:
the sub O's and H's stand for oxygen and hydrogen.
The 2's cancel out.
Also, oxygen gas has a mass of 32 amu. Hydrogen gas has a mass of 2 amu. Thus,
The momentum of oxygen gas is on average 1/4 of that of hydrogen gas (if my calculations are correct).
Shouldn' it be 4pH by your last step?
It's my understanding heavier gas molecules always carry more momentum at equal kinetic energy.
It's my understanding heavier gas molecules always carry more momentum at equal kinetic energy.
I think he meant the momentum of Hydrogen is 1/4 the momentum of oxygenLet's see.
In a bottle, hydrogen gas and oxygen gas molecules should have the same average kinetic energy (KE)
![]()
where p = momentum, m = mass of a gas molecule, and v = (rms) velocity.
Since the average kinetic energies should be equal for H and O:
![]()
the sub O's and H's stand for oxygen and hydrogen.
The 2's cancel out.
Also, oxygen gas has a mass of 32 amu. Hydrogen gas has a mass of 2 amu. Thus,
![]()
The momentum of oxygen gas is on average 1/4 of that of hydrogen gas (if my calculations are correct).
Yes.Shouldn' it be 4pH by your last step?
It's my understanding heavier gas molecules always carry more momentum at equal kinetic energy.
There is no need for long calculations. Just keep in mind that p = 2* Ke/ v
Since gases at same temperature always have same Ke, the gas with the lower velocity will have higher momentum; thus the heavier gas has more momentum.